During each cycle of operation a refrigerator absorbs 45 cal from the freezer compartment and expels 85 cal to the room. If one cycle occurs every 8.0 s, how many minutes will it take to freeze 500 g of water, initially at 0$\degree$C? (L_v = 80 cal/g)

Question

Quizplus · Accepted Answer

The refrigerator removes 45 cal from the freezer compartment every 8.0 s, so it removes 45 cal / 8.0 s = 5.6 cal/s. To freeze 500 g of water, we need to remove 500 g * 80 cal/g = 40,000 cal. So, it will take 40,000 cal / 5.6 cal/s = 7143 s = 120 min.

During Each Cycle of Operation a Refrigerator Absorbs 45 Cal °\degree°

During Each Cycle of Operation a Refrigerator Absorbs 45 Cal $\degree$