The total electromagnetic power emitted by the sun is 3.8 × 10²⁶ W.What is the radiation pressure on a totally absorbing satellite at the orbit of Mercury,which has an orbital radius of 5.8 × 10¹⁰ m? (c = 3.00 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A,ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)30 µPa B)0.30 µPa C)0.030 µPa D)300 µPa E)3.0 µPa

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Quizplus · Accepted Answer

The radiation pressure is given by P = (1/c) * (E/A), where E is the power and A is the area. The area of the satellite is 4πr^2, where r is the radius of the satellite. The power is given as 3.8 × 10^26 W. The speed of light is 3.00 × 10^8 m/s. The radius of the orbit of Mercury is 5.8 × 10^10 m. Substituting these values into the equation, we get P = (1/3.00 × 10^8 m/s) * (3.8 × 10^26 W / 4π(5.8 × 10^10 m)^2) = 30 µPa.

The Total Electromagnetic Power Emitted by the Sun Is 3