What is the average kinetic energy of an ideal gas molecule at 569°C? (The Boltzmann constant is 1.38 × 10^-23 J/K.) A)1.74 × 10^-20 J B)5.81 × 10^-21 J C)1.18 × 10^-17 J D)3.93 × 10^-19 J

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Quizplus · Accepted Answer

The average kinetic energy ($E_k$) of an ideal gas molecule can be calculated using the formula $E_k = \frac{3}{2}kT$, where $k$ is the Boltzmann constant (1.38 × 10^-23 J/K) and $T$ is the temperature in Kelvin. To convert 569°C to Kelvin, add 273.15 to get 842.15 K. Plugging these values into the formula gives $E_k = \frac{3}{2} \times 1.38 \times 10^{-23} \times 842.15 = 1.74 \times 10^{-20} J$.

What Is the Average Kinetic Energy of an Ideal Gas