What is the energy (in eV)of an optical photon of frequency $6.43 \times 10 ^ { 14 } \mathrm {~Hz}$ (h = 6.626 × 10^-34 J ? s, 1 eV = 1.60 × 10^-19 J) A)2.66 eV B)1.62 eV C)1.94 eV D)3.27 eV

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency of the photon. Substituting the given values, we get E = (6.626 × 10^-34 J s)(6.43 × 10^14 Hz) = 4.25 × 10^-19 J. Converting this to eV, we get E = (4.25 × 10^-19 J)/(1.60 × 10^-19 J/eV) = 2.66 eV.

What Is the Energy (In EV)of an Optical Photon of Frequency