A 45.0-kg sample of ice is at 0.00° C.How much heat is needed to melt it? For water L_F = 334,000 J/kg and L_V = 2.256 × 10⁶ J/kg. A)1.50 × 10⁴_kJ B)4.10 × 10⁶_kJ C)0.00 kJ D)1.02 × 10⁵_kJ

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Quizplus · Accepted Answer

The heat needed to melt the ice is calculated using the formula Q = m * L, where m is the mass of the ice (45.0 kg) and L is the latent heat of fusion for water (334,000 J/kg). Thus, Q = 45.0 kg * 334,000 J/kg = 15,030,000 J or 1.50 × 10^7 J, which is equivalent to 1.50 × 10^4 kJ.

A 450-Kg Sample of Ice Is at 0