A compression at a constant pressure of 200 kPa is performed on 8.00 moles of an ideal monatomic gas. The compression reduces the volume of the gas from $0.200 \mathrm {~m} ^ { 3 }$ to $0.120 \mathrm {~m} ^ { 3 }$ How much work was done by the gas during this process?
A)-16 kJ
B)16 kJ
C)-40 kJ
D)40 kJ
E)0 kJ

Question

Quizplus · Accepted Answer

The work done by the gas during a constant pressure process is given by $ W = P \Delta V $. Here, $ P = 200 \, \text{kPa} = 200,000 \, \text{Pa} $, $ \Delta V = 0.120 \, \text{m}^3 - 0.200 \, \text{m}^3 = -0.080 \, \text{m}^3 $. Thus, $ W = 200,000 \times (-0.080) = -16,000 \, \text{J} = -16 \, \text{kJ} $. The negative sign indicates work done on the gas.

A Compression at a Constant Pressure of 200 KPa Is 0.200 m30.200 \mathrm {~m} ^ { 3 }0.200 m3

A Compression at a Constant Pressure of 200 KPa Is $0.200 \mathrm {~m} ^ { 3 }$