A flatbed truck is carrying a 20.0-kg crate along a level road.The coefficient of static friction between the crate and the bed is 0.400,and the coefficient of kinetic friction is 0.300.What is the maximum acceleration that the truck can have if the crate is to stay in place relative to the truck? A)3.92 m/s² B)7.84 m/s² C)8.00 m/s² D)78.5 m/s² E)196 m/s²

Question

Quizplus · Accepted Answer

The maximum acceleration that the truck can have if the crate is to stay in place is equal to the maximum static friction force between the crate and the bed, which is μsN, where μs is the coefficient of static friction and N is the normal force between the crate and the bed. The normal force is equal to the weight of the crate, which is mg, where m is the mass of the crate and g is the acceleration due to gravity. Therefore, the maximum acceleration is:
a = μsN/m = μsg
Substituting the given values, we get:
a = 0.400 × 9.81 m/s² = 3.92 m/s²
Therefore, the best choice is A.

A Flatbed Truck Is Carrying a 20