Evaluate the integral. ? $\int ( 8 \cos x - 4.1 \sin x - 9.3 ) \mathrm { d } x$ ?
A) $8 \sin x + 4.1 \cos x - 9.3 x + C$
B) $- 8 \sin x + 4.1 \cos x + C$
C) $8 \sin x - 4.1 \cos x - 9.3 x + C$
D) $- 8 \sin x - 4.1 \cos x + C$
E) $8 \sin x - 4.1 \cos x + 9.3 x + C$

Question

Quizplus · Accepted Answer

The integral of $8 \cos x$ is $8 \sin x$, the integral of $-4.1 \sin x$ is $4.1 \cos x$, and the integral of $-9.3$ is $-9.3x$. Adding the constant of integration $C$ gives the complete antiderivative.

Evaluate the Integral ∫(8cos⁡x−4.1sin⁡x−9.3)dx\int ( 8 \cos x - 4.1 \sin x - 9.3 ) \mathrm { d } x∫(8cosx−4.1sinx−9.3)dx

Evaluate the Integral $\int ( 8 \cos x - 4.1 \sin x - 9.3 ) \mathrm { d } x$