Calculate q when 28.6 g of water is heated from 22.0$\degree$C to 78.3$\degree$C.

Question

Quizplus · Accepted Answer

To calculate heat (q), we can use the formula:

q = mCΔT

where:
m = mass of water = 28.6 g
C = specific heat capacity of water = 4.184 J/g°C
ΔT = change in temperature = (78.3°C - 22.0°C) = 56.3°C

First, we need to convert the mass of water from grams to kilograms:

m = 28.6 g = 0.0286 kg

Now we can plug in the values:

q = (0.0286 kg)(4.184 J/g°C)(56.3°C) 
q = 6.74 kJ

Therefore, the answer is C because 6.74 kJ is the only option that matches the calculated value of q.

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