TiCl₄ (189.68 g/mol), a source of Ti metal, can be produced from titanium dioxide (79.87 g/mol), carbon (12.01 g/mol), and chlorine gas (70.90 g/mol).Identify the limiting reactant if 195 g TiO₂ and 325 g Cl₂ react in the presence of excess C.Assuming 100% yield, calculate the mass of TiCl ₄ produced.
3 Ti O₂ (s) + 4 C(s) + 6 CL₂ (g) $\rightarrow$ 3 Ti CL₄ (s) + 2 CO₂ (g) + 2 CO(g)

Question

TiCl₄ (189.68 g/mol), a source of Ti metal, can be produced from titanium dioxide (79.87 g/mol), carbon (12.01 g/mol), and chlorine gas (70.90 g/mol).Identify the limiting reactant if 195 g TiO₂ and 325 g Cl₂ react in the presence of excess C.Assuming 100% yield, calculate the mass of TiCl ₄ produced.
3 Ti O₂ (s) + 4 C(s) + 6 CL₂ (g)

\rightarrow

3 Ti CL₄ (s) + 2 CO₂ (g) + 2 CO(g)

Quizplus · Accepted Answer

The Answer of TiCl₄ (189.68 g/mol), a source of Ti metal, can be produced from titanium dioxide (79.87 g/mol), carbon (12.01 g/mol), and chlorine gas (70.90 g/mol).Identify the limiting reactant if 195 g TiO₂ and 325 g Cl₂ react in the presence of excess C.Assuming 100% yield, calculate the mass of TiCl ₄ produced. 3 Ti O₂ (s) + 4 C(s) + 6 CL₂ (g) $\rightarrow$ 3 Ti CL₄ (s) + 2 CO₂ (g) + 2 CO(g)

TiCl4 (189 →\rightarrow→ 3 Ti CL4 (S) + 2 CO2 (G) + 2

TiCl₄ (189 $\rightarrow$ 3 Ti CL₄ (S) + 2 CO₂ (G) + 2