Acrylonitrile (C₃H₃N, 53.07 g/mol) can be produced from propylene (C₃H₆, 42.09 g/mol) according to the reaction shown below.In a particular experiment, 125 g C₃H₆ reacts with 175 g NO (30.01 g/mol) and 105 g C₃H₃N is produced.What is the percent yield for the reaction?
4 C₃ H₆ (g) + 6 NO(g) $\rightarrow$ 4 C₃ H₃ N(l) +6 H₂ O(l) + N₂ (g)

Question

Acrylonitrile (C₃H₃N, 53.07 g/mol) can be produced from propylene (C₃H₆, 42.09 g/mol) according to the reaction shown below.In a particular experiment, 125 g C₃H₆ reacts with 175 g NO (30.01 g/mol) and 105 g C₃H₃N is produced.What is the percent yield for the reaction?
4 C₃ H₆ (g) + 6 NO(g)

\rightarrow

4 C₃ H₃ N(l) +6 H₂ O(l) + N₂ (g)

Quizplus · Accepted Answer

The Answer of Acrylonitrile (C₃H₃N, 53.07 g/mol) can be produced from propylene (C₃H₆, 42.09 g/mol) according to the reaction shown below.In a particular experiment, 125 g C₃H₆ reacts with 175 g NO (30.01 g/mol) and 105 g C₃H₃N is produced.What is the percent yield for the reaction? 4 C₃ H₆ (g) + 6 NO(g) $\rightarrow$ 4 C₃ H₃ N(l) +6 H₂ O(l) + N₂ (g)

Acrylonitrile (C3H3N, 53 →\rightarrow→ 4 C3 H3 N(l) +6 H2 O(l) + N2 (G)

Acrylonitrile (C₃H₃N, 53 $\rightarrow$ 4 C₃ H₃ N(l) +6 H₂ O(l) + N₂ (G)