Measurements show that it takes $0.30 \mathrm {~mJ}$ of work to move $5.0 - \mu \mathrm { C }$ of charge from one plate to another of a certain air-filled capacitor while the potential difference between these plates is kep constant. What is the potential difference between the plates of this capacitor?

Question

Quizplus · Accepted Answer

The potential difference (V) can be calculated using the formula $V = \frac{W}{Q}$, where $W$ is the work done in joules and $Q$ is the charge in coulombs. Converting $0.30 \mathrm {~mJ}$ to joules gives $0.30 \times 10^{-3} \mathrm {~J}$, and $5.0 \mu \mathrm {C}$ to coulombs gives $5.0 \times 10^{-6} \mathrm {~C}$. Thus, $V = \frac{0.30 \times 10^{-3}}{5.0 \times 10^{-6}} = 60 \mathrm {~V}$.

Measurements Show That It Takes 0.30 mJ0.30 \mathrm {~mJ}0.30 mJ Of Work to Move

Measurements Show That It Takes $0.30 \mathrm {~mJ}$ Of Work to Move