A capacitor has a voltage of $391 \mathrm {~V}$ applied across its plates, and then the voltage source is removed. What is the potential difference across its plates if the space between them is then filled with mica, having a dielectric constant of $5.4$ ?

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Quizplus · Accepted Answer

The potential difference across a capacitor's plates decreases when a dielectric material is introduced between them. The new voltage, $V'$, can be found using the formula $V' = V / K$, where $V$ is the initial voltage and $K$ is the dielectric constant. Here, $V' = 391V / 5.4 = 72.4V$, which rounds to $72V$, indicating that the potential difference decreases due to the dielectric's presence.

A Capacitor Has a Voltage Of 391 V391 \mathrm {~V}391 V Applied Across Its Plates, and Then the Voltage Source Is

A Capacitor Has a Voltage Of $391 \mathrm {~V}$ Applied Across Its Plates, and Then the Voltage Source Is