When a 4- $\mu \mathrm { F }$ capacitor has a potential drop of $20 \mathrm {~V}$ across its plates, how much electric potential energy is stored in this capacitor?

Question

Quizplus · Accepted Answer

The electric potential energy stored in a capacitor is given by the equation $U = 1/2 CV^2$, where $C$ is the capacitance and $V$ is the potential difference across the capacitor. In this case, $C = 4 \mu F$ and $V = 20 V$, so the electric potential energy stored in the capacitor is:$$U = 1/2 (4 \mu F)(20 V)^2 = 800 \mu J$$

When a 4- μF\mu \mathrm { F }μF Capacitor Has a Potential Drop Of

When a 4- $\mu \mathrm { F }$ Capacitor Has a Potential Drop Of