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A Loop of Diameter D = 12 Cm, Carrying a Current

Question 87

Multiple Choice

A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field = (0.2 T) + (0.4 T) . The normal to the loop is parallel to the unit vector . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J = (0.2 T) A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field = (0.2 T) + (0.4 T) . The normal to the loop is parallel to the unit vector . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J + (0.4 T) A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field = (0.2 T) + (0.4 T) . The normal to the loop is parallel to the unit vector . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J . The normal to the loop is parallel to the unit vector A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field = (0.2 T) + (0.4 T) . The normal to the loop is parallel to the unit vector . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J . What is the potential energy of the loop?


A) -4.5 × 10-4 J
B) +9.0 × 10-4 J
C) -9.0 × 10-4 J
D) -2.3 × 10-4 J
E) +4.5 × 10-4 J

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