In a Hall experiment a conducting strip of thickness d = 100 μm is placed in a magnetic field B = 0.0 5 T. The magnetic field is perpendicular to the direction of the strip along which there is a 10-A current. What is the Hall voltage measured across the strip if the charge carrier density is 2.5 × 10²⁸/m³ in this material?

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The Hall voltage is given by:$$V_H = \frac{IB}{nqd}$$where:* I is the current* B is the magnetic field* n is the charge carrier density* q is the charge of the charge carriers* d is the thickness of the conducting stripPlugging in the given values, we get:$$V_H = \frac{(10 	ext{ A})(0.05 	ext{ T})}{(2.5 	imes 10^{28} 	ext{/m}^3)(1.6 	imes 10^{-19} 	ext{ C})(100 	imes 10^{-6} 	ext{ m})}$$$$V_H = 1.3 \mu V$$

In a Hall Experiment a Conducting Strip of Thickness D