Calculate the amount of heat energy required to evaporate 27.5 g of water at 100.0 $\degree$C.(molar heat of vaporization of liquid water = 4.07 x 10⁴ J/mol)

Question

Quizplus · Accepted Answer

To find the heat energy required, first convert the mass of water to moles using the molar mass of water (18.015 g/mol). Then multiply the number of moles by the molar heat of vaporization. The calculation is: (27.5 g / 18.015 g/mol) * 4.07 x 10^4 J/mol = 62,100 J = 62.1 kJ.

Calculate the Amount of Heat Energy Required to Evaporate 27 °\degree°

Calculate the Amount of Heat Energy Required to Evaporate 27 $\degree$