Calculate the amount of heat energy required to melt 25.0 g of ice at 0.0 $\degree$C.(molar heat of fusion of ice = 6.01 x 10³ J/mol)

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the amount of moles of ice:

moles of ice = 25.0 g / 18.015 g/mol (molar mass of water) 
moles of ice = 1.387 mol

Now, using the molar heat of fusion of ice, we can calculate the amount of heat energy required to melt this amount of ice:

q = moles of ice x molar heat of fusion of ice 
q = 1.387 mol x 6.01 x 10^3 J/mol 
q = 8.33 x 10^3 J

Converting to kJ: 
q = 8.33 x 10^3 J / 1000 
q = 8.34 kJ

Thus, the answer is (B) 8.34 kJ.

Calculate the Amount of Heat Energy Required to Melt 25 °\degree°