Calculate the Amount of Heat Energy Required to Convert 27 $\degree$

Calculate the amount of heat energy required to convert 27.5 g of water at 62.5 $\degree$ C to steam at 124.0 $\degree$ C.(C_water = 4.18 J/g $\degree$ C; C_ice = 2.03 J/g^oC; C_steam = 2.02 J/g $\degree$ C; molar heat of fusion of ice = 6.01 x 10³ J/mol; molar heat of vaporization of liquid water = 4.07 x 10⁴ J/mol)

A) 6.15 x 10⁴ kJ
B) 1.23 x 10² kJ
C) 4.31 x 10² kJ
D) 31.8 kJ
E) 1.33 kJ