Add.
-$$\frac { 3 } { x } + \frac { 8 } { x - 9 }$$
A) $\frac { 11 x - 27 } { x ( x - 9 ) }$
B) $\frac { 11 x - 27 } { x ( 9 - x ) }$
C) $\frac { 27 x - 11 } { x ( 9 - x ) }$
D) $\frac { 27 x - 11 } { x ( x - 9 ) }$

Question

Quizplus · Accepted Answer

To add the fractions, find a common denominator, which is $x(x-9)$. Then, rewrite each fraction with the common denominator and add: $\frac{3(x-9)}{x(x-9)} + \frac{8x}{x(x-9)} = \frac{3x - 27 + 8x}{x(x-9)} = \frac{11x - 27}{x(x-9)}$.

Add - 3x+8x−9\frac { 3 } { x } + \frac { 8 } { x - 9 }x3​+x−98​

Add
- $\frac { 3 } { x } + \frac { 8 } { x - 9 }$