Consider the reaction CuI(s) ⇄ Cu⁺(aq) + I⁻(aq)
If the concentrations of the Cu⁺ and I⁻ ions in equilibrium at 298 K are both equal to 1.03 × 10⁻⁶ M, what is the value of ΔG° for the reaction?

Question

Quizplus · Accepted Answer

The equation for ΔG° is ΔG° = -RTlnK. We need to find the equilibrium constant (K) for the reaction, which can be calculated using the concentrations of the products and reactants at equilibrium. K = [Cu⁺][I⁻]/[CuI] We are given that the concentrations of both product ions are equal to 1.03 × 10⁻⁶ M. The concentration of CuI can be assumed to be negligible in comparison, since it is a solid and doesn't really have a concentration. Thus, we can simplify the equation to: K = [Cu⁺][I⁻] Substituting the given values, we get: K = (1.03 × 10⁻⁶)2 = 1.06 × 10⁻² Now we can use this value of K to calculate ΔG°: ΔG° = -RTlnK R = 8.31 J/mol·K (gas constant) T = 298 K (temperature) ΔG° = -(8.31 J/mol·K)(298 K) ln(1.06 × 10⁻²) ΔG° = -68.4 kJ Therefore, the answer is B) 68 kJ.

Consider the Reaction CuI(s) ⇄ Cu+(aq) + I−(aq)

Consider the Reaction CuI(s) ⇄ Cu⁺(aq) + I⁻(aq)