What is the difference in frequency for spectral lines emitted by hydrogen for transitions from the n = 16 level to the n = 2 level and transitions from the n = 15 level to the n = 2 level? (R_H = 1.097 × 10⁷ m−¹.) A) 5.65 × 10−¹³ Hz B) 31 Hz C) 1.77 × 10¹² Hz D) 2.55 × 10¹⁶ Hz E) 1.02 × 10¹⁷ Hz

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Quizplus · Accepted Answer

The frequency difference can be calculated using the Rydberg formula for hydrogen. The difference in frequency is given by Δf = R_H * c * (1/2^2 - 1/16^2) - R_H * c * (1/2^2 - 1/15^2), where c is the speed of light. This results in approximately 1.77 × 10^12 Hz.

What Is the Difference in Frequency for Spectral Lines Emitted