The metabolism of one mole of glucose, C₆H₁₂O₆, releases 670 kcal of heat. How much heat is released by the combustion of 0.300 moles of glucose?

Question

Quizplus · Accepted Answer

First, we need to calculate the heat released by the combustion of one mole of glucose:

1 mole of glucose = 670 kcal

Then, we can use a proportion to find the heat released by 0.300 moles:

1 mole of glucose / 670 kcal = 0.300 moles of glucose / x kcal

x = (0.300 moles of glucose x 670 kcal) / 1 mole of glucose

x = 201 kcal

Therefore, the heat released by the combustion of 0.300 moles of glucose is 201 kcal, which is closest to choice B.

The Metabolism of One Mole of Glucose, C6H12O6, Releases 670