If the K_sp of SrSO₄(s) is 3.8 × 10⁻⁴, the concentration of [SO₄^2-] in a saturated solution of SrSO₄(s) is 9.1 × 10⁻¹² M.

Question

Quizplus · Accepted Answer

The Ksp expression for SrSO4(s) is:Ksp = [Sr2+][SO42-]Since the concentration of [Sr2+] is equal to the concentration of [SO42-], we can substitute x for both concentrations:Ksp = x^2Solving for x, we get:x = sqrt(Ksp) = sqrt(3.8 × 10^-4) = 1.95 × 10^-2 MTherefore, the concentration of [SO42-] in a saturated solution of SrSO4(s) is 1.95 × 10^-2 M, which is not equal to 9.1 × 10^-12 M.

If the Ksp of SrSO4(s) Is 3

If the K_sp of SrSO₄(s) Is 3