How many grams of H₂SO₄ are present in 75.0 mL of 12.0 M H₂SO₄?
Molar Mass (H₂SO₄) = 98.09 g/mol

Question

How many grams of H₂SO₄ are present in 75.0 mL of 12.0 M H₂SO₄? Molar Mass (H₂SO₄) = 98.09 g/mol

Quizplus · Accepted Answer

We can use the formula: moles = concentration x volume First, we need to calculate the number of moles of H₂SO₄ in 75.0 mL of 12.0 M solution: moles = 12.0 mol/L x 0.0750 L = 0.9 mol Next, we can use the molar mass of H₂SO₄ to convert moles to grams: grams = moles x molar mass grams = 0.9 mol x 98.09 g/mol = 88.3 g Therefore, there are 88.3 g of H₂SO₄ present in 75.0 mL of 12.0 M solution.

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