How many moles of Na₃PO₄ are present in 5.00 mL of a 0.226 molar solution?

Question

Quizplus · Accepted Answer

First, we need to determine the formula weight of Na₃PO₄: Na₃PO₄ = 23.0 + 32.1 + (4x16.0) + 30.9 + (4x16.0) + 32.1 + (4x16.0) = 322.2 g/mol Next, we can use the formula: moles = concentration (in mol/mL) x volume (in mL) to calculate the number of moles of Na₃PO₄ in 5.00 mL of the 0.226 molar solution: moles = 0.226 mol/mL x 0.00500 L = 0.00113 mol Finally, we can convert moles to scientific notation to match the format in the answer choices: moles = 1.13 x 10^-3 mol Therefore, the answer is choice A: 1.13 x 10^-3 mol.

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