How many moles of OH^- ions are present in 422 mL of a 1.21 molar solution of Ba(OH)₂?

Name: How many moles of OH - ions are present in 422 mL of a 1.21 molar solution of Ba(OH) 2 ?
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Question

Quizplus · Accepted Answer

Ba(OH)₂ dissociates into one Ba²⁺ ion and two OH⁻ ions. Therefore, a 1.21 M solution of Ba(OH)₂ will produce 2 * 1.21 M = 2.42 M of OH⁻ ions. The volume of the solution is 0.422 L. Thus, the moles of OH⁻ ions = 2.42 M * 0.422 L = 1.02 mol.

How Many Moles of OH - Ions Are Present

How Many Moles of OH^- Ions Are Present