How many grams of potassium sulfate are needed to prepare 2.44 L of a 0.0333 molar solution of potassium sulfate?

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the number of moles of potassium sulfate required to prepare the solution.

Molarity = moles of solute / liters of solution

0.0333 M = x / 2.44 L

x = 0.081132 moles

Next, we need to use the molar mass of potassium sulfate to convert moles to grams.

molar mass of K2SO4 = 174.259 g/mol

mass = moles x molar mass

mass = 0.081132 mol x 174.259 g/mol

mass = 14.2 g

Therefore, the answer is D) 14.2 g.

How Many Grams of Potassium Sulfate Are Needed to Prepare