How many moles of K⁺ ions are present in 2.00 L of a 0.211 molar solution of K₂SO₄?

Question

Quizplus · Accepted Answer

We need to use the mole concept and stoichiometry to determine the number of moles of K⁺ ions in the given solution. First, we need to write a balanced equation for the dissociation of K₂SO₄: K₂SO₄ -> K+ + ⁺ From the equation, we see that one mole of K₂SO₄ dissociates to form one mole of ⁺ ions. Next, we use the formula: moles = molarity x volume to calculate the number of moles of K₂SO₄ in 2.00 L of a 0.211 molar solution: moles of K₂SO₄ = 0.211 mol/L x 2.00 L = 0.422 mol Since one mole of K₂SO₄ dissociates to form one mole of ⁺ ions, the number of moles of ⁺ ions in 2.00 L of the solution is also 0.422 mol. Therefore, the answer is B, 0.844 mol (since there are two different ions present in one mole of ⁺).

How Many Moles of K+ Ions Are Present in 2

How Many Moles of K⁺ Ions Are Present in 2