What mass of Ga(OH)₃ is formed from mixing 12.4 mL of 0.332 molar Ga(NO₃)₃ with 9.11 mL of 1.23 molar LiOH?

Name: What mass of Ga(OH) 3 is formed from mixing 12.4 mL of 0.332 molar Ga(NO 3 ) 3 with 9.11 mL of 1.23 molar LiOH?
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Question

Quizplus · Accepted Answer

The reaction is Ga(NO3)3 + 3LiOH → Ga(OH)3 + 3LiNO3. Calculate moles of Ga(NO3)3 (0.00411 mol) and LiOH (0.0112 mol). Ga(NO3)3 is the limiting reagent. Moles of Ga(OH)3 formed = 0.00411 mol. Mass = 0.00411 mol × 78.03 g/mol = 0.451 g.

What Mass of Ga(OH)3 Is Formed from Mixing 12

What Mass of Ga(OH)₃ Is Formed from Mixing 12