What mass of PbCl₂ is formed from mixing 0.334 L of 0.112 molar NaCl witH₂ .12 L of 0.0343 molar Pb(NO₃)₂?

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Quizplus · Accepted Answer

The reaction is Pb(NO3)2 + 2NaCl → PbCl2 + 2NaNO3. Moles of NaCl = 0.334 L * 0.112 M = 0.0374 mol. Moles of Pb(NO3)2 = 0.12 L * 0.0343 M = 0.004116 mol. Pb(NO3)2 is the limiting reagent. Moles of PbCl2 formed = 0.004116 mol. Mass of PbCl2 = 0.004116 mol * 278.1 g/mol = 1.144 g.

What Mass of PbCl2 Is Formed from Mixing 0

What Mass of PbCl₂ Is Formed from Mixing 0