What volume of 0.128 M HCl is needed to neutralize 2.87 grams of Mg(OH) 2 as shown in the unbalanced reaction below?
Molar Mass Mg(OH) 2 = 58.32 g/mol __ HCl + __ Mg(OH) 2→__ MgCl2 + __ H2O (unbalanced reaction)
A) 3.15×10 - 3 L
B) 1.26×10 - 2 L
C) 0.192 L
D) 0.384 L
E) 0.769 L
Correct Answer:
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