How many mL of 1.0 molar HNO₃ will neutralize 0.237 g of Mg(OH)₂?

Question

Quizplus · Accepted Answer

The molar mass of Mg(OH)₂ is approximately 58.32 g/mol. The number of moles of Mg(OH)₂ is 0.237 g / 58.32 g/mol = 0.00406 mol. The balanced equation for the reaction is Mg(OH)₂ + 2HNO₃ → Mg(NO₃)₂ + 2H₂O, so 2 moles of HNO₃ are needed per mole of Mg(OH)₂. Therefore, 0.00406 mol of Mg(OH)₂ requires 0.00812 mol of HNO₃. Since the solution is 1.0 M, 0.00812 mol of HNO₃ is contained in 8.12 mL of solution, which rounds to 8.1 mL.

How Many ML of 1