What is the percent of chlorine in an ionic compound if a 1.23 g sample dissolves in water and reacts with excess AgNO₃ solution to yield 1.45 g of AgCl?

Question

Quizplus · Accepted Answer

To find the percent of chlorine, first calculate the moles of AgCl formed: 1.45 g AgCl / 143.32 g/mol = 0.0101 mol. Since the ratio of AgCl to Cl is 1:1, there are 0.0101 mol of Cl. The mass of Cl is 0.0101 mol * 35.45 g/mol = 0.358 g. The percent of chlorine is (0.358 g / 1.23 g) * 100% = 29.1%, which rounds to 29.2%.

What Is the Percent of Chlorine in an Ionic Compound