Exhibit 4-3 Consider the Acid-Base neutralization of sulfuric acid with sodium hydroxide to answer the following question(s) . NaOH (aq) + H₂SO₄→
-Refer to Exhibit 4-3. If 26.87 mL of a standard 0.1650 M NaOH solution is required to neutralize 39.70 mL of a H₂SO₄ solution, what is the molarity of the H₂SO₄ acid solution?

Question

Quizplus · Accepted Answer

The correct answer is A.To determine the molarity of the H2SO4 solution, we can use the formula:M1V1 = M2V2where M1 and V1 represent the molarity and volume of the NaOH solution, and M2 and V2 represent the molarity and volume of the H2SO4 solution.Substituting the given values into the formula:0.1650 M * 26.87 mL = M2 * 39.70 mLSolving for M2:M2 = (0.1650 M * 26.87 mL) / 39.70 mL = 0.05584 MTherefore, the molarity of the H2SO4 acid solution is 0.05584 M.

Exhibit 4-3 Consider the Acid-Base Neutralization of Sulfuric Acid with Sodium