What is the concentration of a H₂SO₄ solution if experiment shows that 55.7 mL of the solution neutralizes the base in 0.742 g of LiOH?

Question

Quizplus · Accepted Answer

First, we need to write the balanced equation for the reaction between H₂SO₄ and LiOH: H₂SO₄ + LiOH -> H2O + LiH₂SO₄ From the equation, we can see that 1 mole of H₂SO₄ reacts with 1 mole of LiOH to produce 1 mole of LiH₂SO₄. Next, we need to calculate the number of moles of LiOH: moles of LiOH = mass/molar mass = 0.742 g / 23.95 g/mol = 0.031 moles Since 1 mole of H₂SO₄ reacts with 1 mole of LiOH, the number of moles of H₂SO₄ in the solution is also 0.031. Finally, we can calculate the concentration of the solution: concentration = moles/volume = 0.031 moles / 0.557 L = 0.278 M Therefore, the answer is C: 0.278 molar.

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