How many calories of heat are required to heat 52.7 g of Aluminum from 100 ° C to 285 ° C?
Specific Heat(Al) = 0.22 cal/g × ° C

Name: How many calories of heat are required to heat 52.7 g of Aluminum from 100 ° C to 285 ° C? Specific Heat(Al) = 0.22 cal/g × ° C
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Quizplus · Accepted Answer

The heat required is calculated using the formula: Q = mcΔT. Here, m = 52.7 g, c = 0.22 cal/g°C, and ΔT = 285°C - 100°C = 185°C. Thus, Q = 52.7 g × 0.22 cal/g°C × 185°C = 2.1×10³ cal.

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