A possible Lewis structure for BF 3 is given below. 
Why does this resonance form contribute very little to the true electronic structure for this molecule?
A) The formal charge of the Boron atom is +3 and the formal charge of each Flourine atom is - 1. This provides a charge separated compound.
B) The formal charge of the Boron atom is - 1 and the formal charge of the top Flourine atom is +1. This places a negative charge on a metal and a positive charge on a highly electronegative non-metal atom.
C) It does not obey the octet rule for Boron.
D) It does not obey the octet rule for each Flourine.
E) It does not use the proper number of valence electrons.
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