Calculate the energy of activation of a first order reaction, if the rate constants are k 1 = 4.9×10 - 4 L/mol × s for T 1 = 400 K and k 2 = 0.18 L/mol × s for T 2 = 500 K and R = 8.314 J/mol × K.
A) 5.5×104 J/mol
B) 9.8×104 J/mol
C) - 9.8×104 J/mol
D) 2.78×107 J/mol
E) - 5.5×104 J/mol
Correct Answer:
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