What is the partial pressure equilibrium constant, K p , for the following reaction if the concentration equilibrium constant K c = 7.17*10¹⁵ at 200 K?
N₂(g) + 3 H₂ (g) 2 NH₃(g)

Question

What is the partial pressure equilibrium constant, K p , for the following reaction if the concentration equilibrium constant K c = 7.17*10¹⁵ at 200 K? N₂(g) + 3 H₂ (g) 2 NH₃(g)

Quizplus · Accepted Answer

The partial pressure equilibrium constant (Kp) can be related to the concentration equilibrium constant (Kc) using the equation:
Kp = Kc(RT)^(Δn)
where R is the gas constant, T is the temperature in Kelvin, and Δn is the difference in the number of moles of gas between products and reactants. For the given reaction:
N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)
Δn = (2 - 1 - 3) = -2
Substituting the values into the equation:
Kp = Kc(RT)^(-2)
Kp = 7.17×10^(15)(0.0821)(200)^(-2)^(2) ≈ 2.66×10^(13)
Therefore, the correct answer is B.

What Is the Partial Pressure Equilibrium Constant, K P