At a certain temperature K c = 9.0 for the equilibrium N₂O₄ (g) 2 NO₂ . What is K c at the same temperature for:
NO₂ (g) 1 / 2 N₂O₄ (g)

Question

At a certain temperature K c = 9.0 for the equilibrium N₂O₄ (g) 2 NO₂ . What is K c at the same temperature for: NO₂ (g) 1 / 2 N₂O₄ (g)

Quizplus · Accepted Answer

To find the new equilibrium constant, we can use the following relationship: Kc = ([products]/[reactants])^(coefficients) For the given equation: N₂O₄ (g) 11ebff50_c8af_c18f_8da6_8ffe6522a02e_TBX8714_11 2 NO₂ Kc = [NO₂]^2/[N₂O₄] For the new equation: NO₂ (g) 11ebff50_c8af_c190_8da6_2dded2929ee0_TBX8714_11 1 / 2 N₂O₄ (g) Kc = [1/2 N₂O₄]/[NO₂] Kc = 1/2 * [N₂O₄]/[NO₂] Kc = 1/(2Kc[NO₂]^2) Substituting Kc = 9.0 and rearranging the equation: Kc = 1/(2 x 9.0 x [NO₂]^2) Kc = 0.055/[NO₂]^2 Therefore, the equilibrium constant for the new equation is Kc = 0.055/[NO₂]^2. To compare the new Kc with the old Kc, we can use the relationship: (Kc2)/(Kc1) = ([products]2/[reactants]2)/([products]1/[reactants]1) In this case, [reactants]1 and [products]1 are the same as [reactants]2 and [products]2, respectively. Therefore, the equation simplifies to: (Kc2)/(Kc1) = 1/([reactants]/[products]) (Kc2)/(Kc1) = 1/([N₂O₄] x [NO₂]^2)/([NO₂]^2) (Kc2)/(Kc1) = [NO₂]^2/[N₂O₄] (Kc2)/(9.0) = 1/2 Kc2 = 0.33 Therefore, the answer is choice C, 0.33.

At a Certain Temperature K C = 9