For the reaction 2 KClO₃(s) 2 KCl (s) + 3 O₂(g), K c = 2.0 at 750 C. What is the equilibrium concentration of O₂?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is: Kc = [KCl]²/[KClO3]²[O2]³ Given that Kc = 2.0 at 750 C. Let the equilibrium concentration of O2 be x M. Therefore, [KCl] = [KClO3] = 2.0^(1/2) = 1.41 M Substituting the values in the equilibrium constant expression, 2.0 = (1.41)²/[(1.41)²(x)³] 2.0 = 1.9882/(x)³ x³ = 1.9882/2.0 x = (1.9882/2.0)^(1/3) x = (2.0)^(1/3) ≈ 1.26 M Therefore, the equilibrium concentration of O2 is approximately (2.0)^(1/3) or (2.0)^1/3 M. Hence, the correct answer choice is B.

For the Reaction 2 KClO3(s) 2 KCl (S)

For the Reaction 2 KClO₃(s) 2 KCl (S)