The molar solubility of SrF2 in water is 8.8×10 - 4 M. What is the solubility product constant, K sp, for this substance?
A) K sp = 6.81×10 - 10
B) K sp = 2.73×10 - 9
C) K sp = 7.74×10 - 7
D) K sp = 1.55×10 - 6
E) K sp = 2.64×10 - 3
Correct Answer:
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