What is the concentration of Ag⁺ ions in a saturated solution of Ag₂CrO₄ in water?
K _sp = 9.0×10^{- 12} for Ag₂CrO₄.

Question

What is the concentration of Ag⁺ ions in a saturated solution of Ag₂CrO₄ in water? K _sp = 9.0×10^{- 12} for Ag₂CrO₄.

Quizplus · Accepted Answer

Using the given equilibrium constant and the stoichiometry of the equation, we can set up an ICE table: Ag₂CrO₄ <--> Ag⁺ I: 1 M 0 M 0 M C: -x M -x M +x M E: 1-x M -x M x M Substituting these values into the expression for the equilibrium constant: 9.0×10^{- 12} = x(1-x)/(2x) = (1-x)/2 Solving for x: 9.0×10^{- 12} = (1-x)/2 x = 1 - 2(9.0×10^{- 12}) x = 2.6×10^{- 4} M Therefore, the concentration of Ag⁺ ions in a saturated solution of Ag₂CrO₄ in water is 2.6×10^{- 4} M.

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