The solubility of calcium arsenate, Ca₃(AsO₄)₂, in water is 9.0×10^{- 5} M . The value of the solubility product constant is:

Question

Quizplus · Accepted Answer

The solubility product (Ksp) for calcium arsenate, Ca3(AsO4)2, can be calculated using the solubility given and the dissociation equation: Ca3(AsO4)2(s) ⇌ 3Ca2+(aq) + 2AsO43-(aq). For a solubility (s) of 9.0×10^-5 M, the concentrations of ions in solution are [Ca2+] = 3s = 3(9.0×10^-5) M and [AsO43-] = 2s = 2(9.0×10^-5) M. The Ksp expression is [Ca2+]^3[AsO43-]^2. Substituting the values, Ksp = (3(9.0×10^-5))^3(2(9.0×10^-5))^2 = 6.4×10^-19.

The Solubility of Calcium Arsenate, Ca3(AsO4)2, in Water Is 9

The Solubility of Calcium Arsenate, Ca₃(AsO₄)₂, in Water Is 9