What volume of 0.200 M HCl is required to completely neutralize 50.00 mL of 0.150 M KOH?

Question

Quizplus · Accepted Answer

The neutralization reaction between HCl and KOH is a 1:1 molar reaction. To find the volume of HCl needed, use the equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of HCl, and M2 and V2 are the molarity and volume of KOH. Plugging in the values: (0.200 M)(V1) = (0.150 M)(50.00 mL), solving for V1 gives V1 = (0.150 M * 50.00 mL) / 0.200 M = 37.5 mL.

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