For the reaction, N₂(g)+ 3 H₂(g)→ 2 NH₃(g), ΔH° = −92.38 kJ per mole of nitrogen gas.What is the value of ΔH° for the reaction, NH₃(g)→ 1/2 N₂(g)+ 3/2 H₂(g)?

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The Answer of For the reaction, N₂(g)+ 3 H₂(g)→ 2 NH₃(g), ΔH° = −92.38 kJ per mole of nitrogen gas.What is the value of ΔH° for the reaction, NH₃(g)→ 1/2 N₂(g)+ 3/2 H₂(g)?

For the Reaction, N2(g)+ 3 H2(g)→ 2 NH3(g), ΔH° =

For the Reaction, N₂(g)+ 3 H₂(g)→ 2 NH₃(g), ΔH° =