Using the standard enthalpies of formation, ΔH°_f: CO(g)= -110.5 kJ mol⁻¹ CO(NH₂)₂(s)= −333.19 kJ mol⁻¹ NH₃(g)= −46.19 kJ mol⁻¹calculate ΔH°_reaction for CO(NH₂)₂(s)+ H₂(g)→ 2NH₃(g)+ CO(g)

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The Answer of Using the standard enthalpies of formation, ΔH°_f: CO(g)= -110.5 kJ mol⁻¹ CO(NH₂)₂(s)= −333.19 kJ mol⁻¹ NH₃(g)= −46.19 kJ mol⁻¹calculate ΔH°_reaction for CO(NH₂)₂(s)+ H₂(g)→ 2NH₃(g)+ CO(g)

Using the Standard Enthalpies of Formation, ΔH°f: CO(g)= -110

Using the Standard Enthalpies of Formation, ΔH°_f: CO(g)= -110