Complete combustion of hydrocarbons or compounds with C,H, and O as the only elements give CO₂ and H₂O as the only products. If carried out under standard conditions, the CO₂ is a gas and the H₂O is a liquid. Given these standard enthalpies of combustion:CH₃CHO(l)= −1166.37 kJ mol⁻¹, C₆H₁₂O₃(l)= −3340.34 kJ mol⁻¹, H₂(g)= −285.90 kJ mol⁻¹,C(s)= −393.50 kJ mol⁻¹, calculate ΔH°_reaction for the process, 3 CH₃CHO(l)→ C₆H₁₂O₃(l).Remember it is always products minus reactants when performing enthalpy calculations.

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The Answer of Complete combustion of hydrocarbons or compounds with C,H, and O as the only elements give CO₂ and H₂O as the only products. If carried out under standard conditions, the CO₂ is a gas and the H₂O is a liquid. Given these standard enthalpies of combustion:CH₃CHO(l)= −1166.37 kJ mol⁻¹, C₆H₁₂O₃(l)= −3340.34 kJ mol⁻¹, H₂(g)= −285.90 kJ mol⁻¹,C(s)= −393.50 kJ mol⁻¹, calculate ΔH°_reaction for the process, 3 CH₃CHO(l)→ C₆H₁₂O₃(l).Remember it is always products minus reactants when performing enthalpy calculations.

Complete Combustion of Hydrocarbons or Compounds with C,H, and O