Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid. Which is the limiting reagent when 28 g of MnO₂ are mixed with 42 g of HCl?
MnO₂(s) + 4HCl(aq) $\rarr$ MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
Hint: Don't forget to include the coefficients in your consideration.

Question

Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid. Which is the limiting reagent when 28 g of MnO₂ are mixed with 42 g of HCl?
MnO₂(s) + 4HCl(aq)

\rarr

MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
Hint: Don't forget to include the coefficients in your consideration.

Quizplus · Accepted Answer

The molar mass of MnO2 is 86.9 g/mol, so 28 g is 0.322 mol. The molar mass of HCl is 36.5 g/mol, so 42 g is 1.15 mol. The reaction requires 4 moles of HCl per mole of MnO2, so 0.322 mol of MnO2 would need 1.288 mol of HCl. Since only 1.15 mol of HCl is available, HCl is the limiting reagent.

Chlorine Gas Can Be Made from the Reaction of Manganese →\rarr→

Chlorine Gas Can Be Made from the Reaction of Manganese $\rarr$